-sin^2x+(2*cosx)+2=0

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Solution for -sin^2x+(2*cosx)+2=0 equation: 


Simplifying
-1sin2x + (2cosx) + 2 = 0

Reorder the terms:
2 + (2cosx) + -1in2sx = 0

Solving
2 + (2cosx) + -1in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + (2cosx) + -2 + -1in2sx = 0 + -2

Reorder the terms:
2 + -2 + (2cosx) + -1in2sx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + (2cosx) + -1in2sx = 0 + -2
(2cosx) + -1in2sx = 0 + -2

Combine like terms: 0 + -2 = -2
(2cosx) + -1in2sx = -2

Add 'in2sx' to each side of the equation.
(2cosx) + -1in2sx + in2sx = -2 + in2sx

Combine like terms: -1in2sx + in2sx = 0
(2cosx) + 0 = -2 + in2sx
(2cosx) = -2 + in2sx

Divide each side by '(2osx)'.
c = -1o-1s-1x-1 + 0.5in2o-1

Simplifying
c = -1o-1s-1x-1 + 0.5in2o-1

Reorder the terms:
c = 0.5in2o-1 + -1o-1s-1x-1

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